From a pack of 52 cards, two cards are drawn at random. Then the probability that one is a king and the other is a queen is

$\begin {array} {1 1} (A)\;\large\frac{4}{663} & \quad (B)\;\large\frac{6}{663} \\ (C)\;\large\frac{2}{663} & \quad (D)\;\large\frac{8}{663} \end {array}$

Total number of cases = $52C_2$
$\therefore$ Required probability = $\large\frac{4C_1 \times 4C_1}{52C_2}$
$= \large\frac{16}{26 \times 51}$
$= \large\frac{8}{663}$
Ans : (D)
answered Jan 15, 2014