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The probability that the same number appear on throwing three dice simultaneously is

$\begin {array} {1 1} (A)\;\large\frac{1}{36} & \quad (B)\;\large\frac{5}{36} \\ (C)\;\large\frac{1}{6} & \quad (D)\;\large\frac{4}{13} \end {array}$

Can you answer this question?

Total number of favourable cases = 6
Total number of cases = 216
Required probability = $\large\frac{6}{216}$
$= \large\frac{1}{36}$
Ans : (A)
answered Jan 15, 2014