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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

The probability that the same number appear on throwing three dice simultaneously is

$\begin {array} {1 1} (A)\;\large\frac{1}{36} & \quad (B)\;\large\frac{5}{36} \\ (C)\;\large\frac{1}{6} & \quad (D)\;\large\frac{4}{13} \end {array}$

 

1 Answer

Total number of favourable cases = 6
Total number of cases = 216
Required probability = $ \large\frac{6}{216}$
$ = \large\frac{1}{36}$
Ans : (A)
answered Jan 15, 2014 by thanvigandhi_1
 

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