# The probability that the same number appear on throwing three dice simultaneously is

$\begin {array} {1 1} (A)\;\large\frac{1}{36} & \quad (B)\;\large\frac{5}{36} \\ (C)\;\large\frac{1}{6} & \quad (D)\;\large\frac{4}{13} \end {array}$

Total number of favourable cases = 6
Total number of cases = 216
Required probability = $\large\frac{6}{216}$
$= \large\frac{1}{36}$
Ans : (A)