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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

Four dice are rolled. The number of possible outcomes in which at least one dice shown 2 is

$\begin {array} {1 1} (A)\;625 & \quad (B)\;671 \\ (C)\;1023 & \quad (D)\;1296 \end {array}$

 

1 Answer

The total number of ways = $6^4$
= 1296
Required number of ways = 1296 - ( none of the number shows 2)
$ = 1296-5^4$
$= 671$
Ans : (B)
answered Jan 15, 2014 by thanvigandhi_1
 

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