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Probability
Four dice are rolled. The number of possible outcomes in which at least one dice shown 2 is
$\begin {array} {1 1} (A)\;625 & \quad (B)\;671 \\ (C)\;1023 & \quad (D)\;1296 \end {array}$
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Jan 15, 2014
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thanvigandhi_1
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Aug 22, 2014
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1 Answer
The total number of ways = $6^4$
= 1296
Required number of ways = 1296 - ( none of the number shows 2)
$ = 1296-5^4$
$= 671$
Ans : (B)
answered
Jan 15, 2014
by
thanvigandhi_1
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