logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

A light wave has wavelength $6000 A^{\circ}$ in vacuum. The wavelength of this light when it passes through a certain glass of refraction index $(\mu =1.5 ) $ is

$(a)\;4000 A^{\circ} \\ (b)\;6000 A^{\circ} \\ (c)\;9000 A^{\circ} \\ (d)\;15000 A ^{\circ} $

Can you answer this question?
 
 

1 Answer

0 votes
$\large\frac{\mu _1}{\mu_2}=\frac{\lambda_2}{\lambda_1}$
$\mu_1$ - refractive index for air
$\mu_2$ - refractive index for glass
$\lambda _1$ -wave length in air
$\lambda _2$ -wave length in glass
$\frac{1}{1.5}=\frac{\lambda_2}{6000}$
$\lambda _m= 4000 A^{\circ}$
Hence a is the correct answer.

 

answered Jan 16, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...