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A light wave has wavelength $6000 A^{\circ}$ in vacuum. The wavelength of this light when it passes through a certain glass of refraction index $(\mu =1.5 ) $ is

$(a)\;4000 A^{\circ} \\ (b)\;6000 A^{\circ} \\ (c)\;9000 A^{\circ} \\ (d)\;15000 A ^{\circ} $

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$\large\frac{\mu _1}{\mu_2}=\frac{\lambda_2}{\lambda_1}$
$\mu_1$ - refractive index for air
$\mu_2$ - refractive index for glass
$\lambda _1$ -wave length in air
$\lambda _2$ -wave length in glass
$\lambda _m= 4000 A^{\circ}$
Hence a is the correct answer.


answered Jan 16, 2014 by meena.p

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