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# Calculate the uncertainty in velocity of a cricket ball (mass=0.15Kg) if its uncertainty position is of the order of $1A^{\large\circ}$

$\begin{array}{1 1}(a)\;3.51\times 10^{-24}m/s&(b)\;2.6\times 10^{-24}m/s\\(c)\;3.51\times 10^{-20}m/s&(d)\;1.6\times 10^{-24}m/s\end{array}$

$\Delta u\Delta x=\large\frac{h}{4\pi m}$
$\Delta u=\large\frac{h}{4\pi m \Delta x}$
$\Rightarrow \large\frac{6.625\times 10^{-34}}{4\times 22/7\times 0.15\times 10^{-10}}$
$\Rightarrow3.51\times 10^{-20}m/s$
Hence (c) is the correct answer.