$\begin{array}{1 1}(a)\;1.14\times 10^{-2}cm&(b)\;2.3\times 10^{-6}cm\\(c)\;1.14\times 10^{-6}cm&(d)\;2.4\times 10^{-3}cm\end{array}$

Let the transition occurs in between the levels $n_1$ and $n_2$.Thus if $n_2 > n_1$,then

$n_1+n_2=4$

$n_2-n_1=2$

$n_1=1$ and $n_2=3$

$\therefore \large\frac{1}{\lambda}$$=R_H\times z^2\big[\large\frac{1}{1^2}-\frac{1}{3^2}\big]$

$z=3$ for Li

$\Rightarrow 109678\times 3^2\times \large\frac{8}{9}$

$\lambda=1.14\times 10^{-6}cm$

Hence (c) is the correct answer.

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