$(a)\;1400m/s\qquad(b)\;1200m/s\qquad(c)\;1235m/s\qquad(d)\;1300m/s$

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+2 votes

+1 vote

$\lambda=\large\frac{h}{mu}$

Momentum ,$mu=\large\frac{h}{\lambda}$

$\Rightarrow \large\frac{6.625\times 10^{-34}}{5200\times 10^{-10}}$$Kgm/s$------(i)

Momentum of electron $=mu=9.108\times 10^{-31}\times u$------(ii)

Since both are same,therefore by (i) & (ii)

$9.108\times 10^{-31}\times u=\large\frac{6.625\times 10^{-34}}{5200\times 10^{-10}}$

$u=1400m/s$

Hence (a) is the correct answer.

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