$(a)\;60^{\circ} \\ (b)\;45^{\circ} \\ (c)\;30^{\circ} \\ (d)\;90^{\circ} $

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$\sin c= \large\frac{\mu_2}{\mu_1} =\frac{\mu \;in \;2nd \;medium}{\mu \;in \;1st \;medium}$

$\qquad= \large\frac{\lambda _1}{\lambda_2}$

$\qquad= \large\frac{wave\;length\; in\; 1st\; medium}{wave\;length\;in\;2nd\;medium}$

$\qquad= \large\frac{2500 \;A^{\circ}}{5000 A^{\circ}}$

$\qquad=\large\frac{1}{2}$

$\therefore$ Critical angle $C=30^{\circ}$

Hence c is the correct answer.

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