Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If f(x)=2x and $g(x)=\Large {\frac{x^2}{2}}\normalsize+1$,then which of the following can be a discontinuous function

\begin{array}{1 1}(A)\;f(x)+g(x) & (B)\;f(x)-g(x)\\(C)\;f(x).g(x) & (D)\;\frac{g(x)}{f(x)}\end{array}

Can you answer this question?

1 Answer

0 votes
  • A function is said to be discontinuous if the $LHL\neq RHL$
  • A function is said to be discontinuous if either the LHL or RHL does not exist.
Step 1:
$f(x)=2x$ and $g(x)=\large\frac{x^2}{2}$$+1$
When function $\large\frac{g(x)}{f(x)}$ can be discontinuous function.
When simplified we get,
Step 2:
When $x=0$ the function is undefined .Hence it does not exist.
The function $\large\frac{g(x)}{f(x)}$ can be discontinuous.
Hence the correct option is $D$
answered Jul 4, 2013 by sreemathi.v
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App