Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two mirror one concave of radius of curvature $0.4\;m$ and another convex mirror of radius of curvature $0.2 \;m$ are kept facing each other which are $0.5\;m$ apart. An object is placed between two mirrors, $0.25\;m$ from concave mirror. Where is the image formed after two reflections.

(a) 0.5 m behind concave mirror

(b) 0.5 m behind convex mirror

(c) 0.125 m behind concave mirror

(d) 0.125 m behind convex mirror

Can you answer this question?

1 Answer

0 votes
The first reflection at concave mirror.
$u = -0.25 m$
$f= \large\frac{r}{2} $$=-0.2\;m$
$\large\frac{1}{f} =\frac{1}{u}+\frac{1}{v}$
$\large\frac{-1}{.2} =\frac{-1}{.25}+\frac{1}{v}$
$v= -1 m$
ie the image forms 1 m in front of the concave mirror ie 0.5 m behind convex mirror.(virtual image ) for reflection at convex mirror
$u= +0.5$
$f =\large\frac{r}{2}$$=+0.1$
$\therefore u= \large\frac{1}{0.1} =\frac{1}{0.5}+\frac{1}{v}$
$v= +0.125\;m$
ie $0.125$ behind convex mirror
Hence d is the correct answer.
answered Jan 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App