(a) 0.5 m behind concave mirror

(b) 0.5 m behind convex mirror

(c) 0.125 m behind concave mirror

(d) 0.125 m behind convex mirror

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(a) 0.5 m behind concave mirror

(b) 0.5 m behind convex mirror

(c) 0.125 m behind concave mirror

(d) 0.125 m behind convex mirror

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The first reflection at concave mirror.

$u = -0.25 m$

$f= \large\frac{r}{2} $$=-0.2\;m$

$\large\frac{1}{f} =\frac{1}{u}+\frac{1}{v}$

$\large\frac{-1}{.2} =\frac{-1}{.25}+\frac{1}{v}$

$v= -1 m$

ie the image forms 1 m in front of the concave mirror ie 0.5 m behind convex mirror.(virtual image ) for reflection at convex mirror

$u= +0.5$

$f =\large\frac{r}{2}$$=+0.1$

$\therefore u= \large\frac{1}{0.1} =\frac{1}{0.5}+\frac{1}{v}$

$v= +0.125\;m$

ie $0.125$ behind convex mirror

Hence d is the correct answer.

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