logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Calculate the uncertainty in velocity of an electron if the uncertainty in its position is of the order of $1A^{\large\circ}$

$\begin{array}{1 1}(a)\;4.8\times 10^5m/s&(b)\;5.8\times 10^5m/s\\(c)\;5.8\times 10^2m/s&(d)\;2.3\times 10^5m/s\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
According to Heisenberg's uncertainty principle
$\Delta u\Delta x\approx \large\frac{h}{4\pi m}$
$\Delta u\approx \large\frac{h}{4\pi m\Delta x}$
$\Rightarrow \large\frac{6.625\times 10^{\Large-34}}{4\times 22/7\times 9.108\times 10^{\Large-31}\times 10^{-10}}$
$\Rightarrow 5.8\times 10^5m/s$
Hence (b) is the correct answer.
answered Jan 17, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...