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If $f(x)=x^2\sin \frac{1}{x}$,when $x\neq0$,then the value of the function f at $x=0$,so that the function is continuous at $x=0$,is

\begin{array}{1 1}(A)\;0 & (B)\;-1\\(C)\;1 & (D)\;none\;of\;these\end{array}

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