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Q)

Which of the following reacts with $BCl_3$ to form diborane

$\begin{array}{1 1}(a)\;NH_3&(b)\;NaHg\\(c)\;LiAlH_4&(d)\;K_2Cr_2O_7\end{array}$

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A)
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$4BCl_3+3LiAlH_4\rightarrow B_2H_6+3LiCl+3AlCl_3$
Hence (c) is the correct answer.
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