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Model Papers
Find the equation of the plane passing through the point ( 1, -1, 2 ) having ( 2, 3, 2 ) as direction ratios of normal to the plane?
cbse
class12
modelpaper
2012
sec-a
q10
math
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asked
Jan 2, 2013
by
thanvigandhi_1
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Find the equation of the plane passing through the line intersection of the plane \( x-2y+z=1\) and \( 2x+y+z=8\) and parallel to the line with direction ratios 1,2,1. Also, find the perpendicular distance of the point P(3,1,2) from this plane.
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If the equation of the line AB is \( \large\frac{x-3}{1} = \frac{y+2}{-2} = \frac{z-5}{4} ,\) find the direction ratios of a line parallel to AB.
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Find the equation of the plane passing through the intersection of planes \( 4x-y+z=10\: and \: x+y-z=4\) and parallel to the line with direction ratios < 2, 1, 1>. Find also the perpendicular distance of (1, 1, 1) from the plane.
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Find the direction cosines of the line passing through the following points (-2,4,-5),(1,2,3)
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Find the direction cosines of a line, passing through origin and lying in the first octant, making equal angles with the three coordinates axes.
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The equation of the plane passing through the point $(1,1,1)$ and having direction ratios $b,c,a$ $(a < b < c)$, where $a,b,c$ are prime factors of $2001$ is ?
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Find the cartesian equation of line which passes through the point ( -2, 4, -5 ) and parallel to the line given by \( \large\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6} \)
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asked
Dec 25, 2012
by
thanvigandhi_1
0
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