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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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The number of terms in the AP a, b,....c is


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Answer : (c) $\;\frac{(b+c-2a)}{(b-a)}$
Explanation : Let d be the common differance of the AP
Then d=b-a
The value of c is given by
Solving this , $ c=2a-b\;+(b-a)n$
answered Jan 17, 2014 by yamini.v

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