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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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The sum of $n$ terms of an arithmetic progression is $\;n\;(2n-1)$. What is the $m^{th}$ term of the series?


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Answer : (c) 4m-3
Explanation : $T_{m}=S_{m}-S_{m-1}=m\;(2m-1)-(m-1)\;[2(m-1)-1]$
answered Jan 18, 2014 by yamini.v

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