Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Let $f(x)=|sin x|$,then

\[\begin{array}{1 1}(A)\;f \;is\;everywhere\;differentiable\\(B)\;f \;is\;everywhere\;continuous\;but\;not\;differentiable\;at\;x=n\pi,n\in z \\(C)\;f\;is\;everywhere\;continuous\;but\;not\;differentiable\;at\;x=(2n+1)\frac{\pi}{2},n\in z\\(D)\;none\;of\;these\end{array} \]

Can you answer this question?

1 Answer

0 votes
  • General solution for $x$ in $\sin x$ is $x=n\pi+(-1)\alpha,n\in z$
$f(x)=\mid \sin x\mid$
The general solution for $\sin x$ is $x=n\pi+(-1)\alpha,n\in z$
Hence $f(x)=\mid \sin x\mid$ is continuous everywhere but not differentiable at $x=n\pi,n\in z$
Hence the correct option is $B$
answered Jul 4, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App