logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
0 votes

Sum of series $S$ = $\frac{1}{2}$+$\frac{1}{3}\;(1+2)$+$\frac{1}{4}\;(1+2+3)$+$\frac{1}{5}\;(1+2+3+4)$+......upto 20 terms is

$(a)\;110\qquad(b)\;105\qquad(c)\;115\qquad(d)\;116$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : (b) 105
Explanation : $k^{th}\;term\;t_{k}=\frac{1}{k+1}\;[1+2+\;.....\;+k]$
$=\frac{1}{k+1}\;\frac{k(k+1)}{2}\;=\frac{k}{2}$
$S=\sum_{k=1}^{20}\;\frac{k}{2}=\frac{1}{2}*\frac{20*21}{2}=105.$
answered Jan 20, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...