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Sum of series $(n)(n)$ + $(n-1)(n+1)$ + $(n-2)(n+2)$ +....+ $1\;(2n-1)$ is

$(a)\;n^3\qquad(b)\;\frac{1}{6}\;n\;(n+1)\;(n+2)\qquad(c)\;\frac{1}{3}n^3-n^2\qquad(d)\;None$

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