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# What happens when chlorides are heated with $NH_4Cl$

$\begin{array}{1 1}(a)\;NH_3+HCl\;is\;given\;out\\(b)\;NH_2+HCl_2\;is\; given\;out\\(c)\;NH_3+H_2O\;is \;given\;out\\(d)\;NaCl+H_2O\;is\;given\;out\end{array}$

$NH_4Cl(s)\qquad\underrightarrow{\Delta}\qquad NH_3(g)+HCl(g)$
Hence (a) is the correct answer.