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A person carrying a plane mirror facing his back is moving with a speed of V m/s. Another person is following the mirror at the speed of u m/s. What is the speed of approach of the person to the image in the mirrors.

$(a)\;u-2v \\ (b)\;v-2u \\ (c)\;v-u \\ (d)2(u-v) $

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The speed with which the person following is approaching the mirror is
$(u-v) m/s$
$\therefore $ the speed with which he is approaching his image in the mirror is $2 (u-v) m/s$
Hence d is the correct answer.
answered Jan 20, 2014 by meena.p
 

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