# What is the contradiction of the statement: In $\Delta ABC,\: if\: AB=AC$, then angles $C=B$?

$\begin {array} {1 1} (A)\;In\: \Delta ABC,\: angles\: C=B \Rightarrow\: AB=AC & \quad (B)\;In \: \Delta ABC, \: angles\: C=B \Rightarrow \: AB \neq AC \\ (C)\;In \: \Delta ABC,\: angles \: C \neq B \Rightarrow AB \neq AC & \quad (D)\;none\: of\: these \end {array}$

Ans : (B)
$In \: \Delta ABC,\: angles\: C=B \Rightarrow \: AB \neq AC$