(a) will be same

(b)will be 2 mm

(c)will be 4 mm

(d)will be 1mm

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Since $10th$ maxima is 3 cm from from central maxima the fringe width $\beta =\large\frac{3}{10}$

$\qquad= 0.3 cm$

$\qquad= 3 mm$

Now when YDSE is immersed in a liquid of refractive index $\mu $ new fring width $\beta'=\large\frac{\beta}{\mu}$

$\qquad= \large\frac{0.3}{1.5} $$=0.2 \;cm$

$\qquad= 2 \;mm$

Hence b is the correct answer

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...