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What is dispersive power of glass if $\mu_v =1.522$ and $\mu_r =1.514$

$(a)\;0.015 \\ (b)\;0.016 \\ (c)\;0.017 \\ (d)\;0.0015 $

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dispersive power $w= \large\frac{\mu_v-\mu_{r}}{\mu -1}$
$\mu= \large\frac{\mu_v+\mu_r}{2}$
$\mu= \large\frac{1.522+1.514}{2}$
$\qquad= \large\frac{3.036}{2}$
$\qquad= 1.518$
$w= \large\frac{1.522 -1.514}{1.518-1}$
$\quad= \large\frac{0.008}{0.518}$
$\quad= 0.01554$
Hence a is the correct answer
answered Jan 21, 2014 by meena.p

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