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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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If the numbers $\;1,x^2,6-x^2\;$ are in GP , then value of $x$ is :


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Answer : (c) $\;\pm\sqrt{2}$
Explanation : For GP
answered Jan 21, 2014 by yamini.v

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