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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Sequence and Series

If the numbers $a, b, c, d, e$ are in AP, the value of $a-4b+6c-4d+e$ is

$(a)\;2c\qquad(b)\;2e\qquad(c)\;2b\qquad(d)\;0$

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1 Answer

Answer : (d) 0
Explanation : $a+e=2c$
$b+d=2c$
$=a-4b+6c-4d+e$
$=2c-4\;(2c)+6c$
$=0.$
answered Jan 21, 2014 by yamini.v
 

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