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Q)

# $xNO_2+yH_2O+O_2\rightarrow 4z$.The $z$ in the equation is

$\begin{array}{1 1}(a)\;HNO_2\\(b)\;NO_2\\(c)\;O_2\\(d)\;HNO_3\end{array}$

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A)
$4NO_2+2H_2O+O_2\rightarrow 4HNO_3$
Hence $z$ is $HNO_3$
Hence (d) is the correct option.