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# $x(CH_2O)\rightarrow CO_2+CH_4$.The $x$ is

$\begin{array}{1 1}(a)\;2\\(b)\;3\\(c)\;4\\(d)\;1\end{array}$

$2(CH_2O)\rightarrow CO_2+CH_4$
Hence x is 2.
Hence (a) is the correct answer.