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$CF_2Cl_2+hv\rightarrow CF_2Cl+A,CFCl_3+hv\rightarrow CFCl_2+B$.Both $A$ and $B$ are same

$\begin{array}{1 1}(a)\;True\\(b)\;False\\(c)\;A\;is\;Cl_2,B\;is\;Cl\\(d)\;None\end{array}$

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$CF_2Cl_2+hv\rightarrow CF_2Cl+Cl$
$CFCl_3+hv\rightarrow CFCl_2+Cl$
$\Rightarrow A$ is $Cl$,$B$ is $Cl$.
Hence $A$ and $B$ are same.
Hence (a) is the correct option.
answered Jan 22, 2014 by sreemathi.v

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