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Ratio of the Bohr radius of protium ,deuterium and tritium atom is

$\begin{array}{1 1}(a)\;1 : 2 :3\\(b)\;1 : 1 : 1\\(c)\;3 : 2 : 1\\(d)\;2 : 3 : 4\end{array}$

1 Answer

$r \propto \large\frac{n^2}{z}$
Hence (b) is the correct answer.
answered Jan 22, 2014 by sreemathi.v
 
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