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The electronic configuration is $1s^1$ for

$\begin{array}{1 1}(a)\;\text{Protium atom}\\(b)\;\text{Deuterium atom}\\(c)\;\text{Tritium atom}\\(d)\;\text{All}\end{array}$

1 Answer

$1^{\Large H^1},1^{\Large H^2},1^{\Large H^3}$ having same electron configuration (i.e) $1s^1$
Hence (d) is the correct option.
answered Jan 22, 2014 by sreemathi.v
 
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