(a)Concave mirror of focal length 10 cm

(b)Convex mirror of focal length 10 cm

(c)Concave mirror of focal length 3.75 cm

(d)Convxe mirror of focal length 2.5 cm

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Since the focal length of equiconvex of $\mu =1.5 \;cm$

$|R_1 |=|R_2|=f=10\;cm$

Power of the combination

$P=2 P_L+P_M$

$-\large\frac{1}{F} =2( \mu-1) \bigg[ \large\frac{1}{R_1} -\frac{1}{R_2}\bigg]-\frac{2}{R_2 }$

$\qquad= 2(1.5 -1) \bigg[ \large\frac{1}{15} -\frac{1}{-15}\bigg] -\frac{2}{-15}$

$\qquad= \large\frac{-1}{F}=\frac{4}{15}$

$F= -\large\frac{-15}{14}$

$\quad= -3.75\;cm$

System behave like concave mirror of focal length $3.75\;cm$

Hence c is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...