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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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One mole of a monoatomic ideal gas is mixed with two moles of a diatomic gas. What is the molar specific heat of the mixture at constant volume?

$\begin{array}{1 1} 2.17\;R \\ 1.83\;R \\ 2R \\ 3.5\;R \end{array}$

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  • Two specific heats are defined for gases, one for constant volume, $C_v$ and one for constant pressure $C_p$.
  • For a monoatomic gas in constant volume, $C_1 = \frac{3}{2} R$, where $R$ is the ideal gas constant.
  • For a diatomic gas in constant volume, $C_2 = \frac{5}{2} R$, where $R$ is the ideal gas constant.
Given a mixture with One mole of a monoatomic ideal gas is mixed with two moles of a diatomic gas.
The specific heat of the mixture $ = C = \large \frac{1 \times C_1 + 2 \times C_2}{3} =$$ \large\frac{ 1 \times \frac{3R}{2} + 2 \times \frac{5R}{2}}{3} $$= 2.17 R$
answered Jan 22, 2014 by balaji.thirumalai
 

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