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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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A pressure-temperature graph of an ideal gas is shown below. Choose the correct alternative (assume equal number of moles of different volumes).

image $(A)\; V_1 = V_2, V_3 = V_4, V_2 \gt V_3$ $(B)\; V_1 = V_2, V_3 = V_4, V_2 \lt V_1$ $(C)\; V_1 = V_2 = V_3 = V_4$ $(D)\; V_4 \gt V_3 \gt V_2 \gt V_1$
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Since $PV = nRT$, the Pressure-Temperature graph at constant volume has a greater slope at lower volume.
Since pt. 2 lies on the line with lesser slope, $V_2 > V_3$.
Since pt. 2 and pt. 1 are on the same line and pts. 3 and 4 are on the same line, $V_1 = V_2$ and $V_3 = V_4$ must hold true, since the P-T graph is a linear one.
answered Jan 22, 2014 by balaji.thirumalai
 

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