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S1:$ ^{\sim} (p \leftrightarrow\: ^{\sim} q)$ is equivalent to $p \leftrightarrow q.$ \[\] S2 :$ ^{\sim} (p\leftrightarrow \: ^{\sim} q)$ is a tautology.

$\begin {array} {1 1} \text{(A) S1 is true, S2 is true,S2 is a correct explanation for S1} \\ \text{(B) S1 is true, S2 is true, S2 is not a correct explanation for S1} \\ \text{(C) S1 is true, S2 is false} \\ \text{(D) S1 is false, S2 is true} \end {array}$

1 Answer

p q $p \leftrightarrow q$ $^{\sim}q$ $p \leftrightarrow \: ^{\sim}q$ $^{\sim} (p \leftrightarrow \: ^{\sim}q)$
T T T F F T
T F F T T F
F T F F T F
F F T T F T
Ans : (C)

 

answered Jan 22, 2014 by thanvigandhi_1
edited Jan 22, 2014 by thanvigandhi_1
 

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