$(a)\;16^{\circ} \\ (b)\;62^{\circ} \\ (c)\;32^{\circ} \\ (d)\;no\;second\; order\; diffraction \;takes \;place $

1st order diffraction

$d \sin \theta =n \lambda$

$\therefore d \sin \theta = \lambda$

$ d \sin 32^{\circ}=\lambda$

For second order

$d \sin \theta_2=2 \lambda$

$\qquad= 2 d \sin 32^{\circ}$

$\sin \theta_2= 2 \sin 32^{\circ}$

$ \sin \theta_2 > 1$

Which is not possible

$\therefore$ no second order diffraction takes places.

Hence d is the correct answer.

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