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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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The temperature versus volume of an ideal gas is shown below.


What does the corresponding PV diagram look like?

$\begin{array}{1 1} a \\ b \\ c \\ d\end{array}$

Can you answer this question?

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For an ideal gas, PV = nRT.
From A to B, process is isochoric with increase in pressure and temperatures.
From B to C, process is isobaric with increasing volume. (Because $T = \large \frac {P}{nR} $$V$, the graph is of the type $y = mx + c$ with slope $m$)
Process C to D is isochoric with decreasing temperature and pressure.
Process D to A is isobaris but with lesser slope and hence lesser pressure.
Hence the PV diagram looks like:
answered Jan 22, 2014 by balaji.thirumalai

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