$(a)\;1\qquad(b)\;3\qquad(c)\;2 \qquad(d)\;4$

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The radius of Bohr's orbit for H-atom

$r_1H=0.529\times10^{-8}cm$

$r_3H=0.529\times 10^{-8}cm\times(3)^{2} cm$

And velocity $u_1 for H-atom = 2.1847\times10^{8}cm/s$

$u_3=\large\frac{u_1}{ n} =\frac{2.1847\times10^{8}}{3}$

since $\lambda=\large\frac{ h}{ mu}$

$\Rightarrow\large\frac{2\times 3.14\times 0.529\times10^{-8}\times 9\times 9.1\times10^{-28}\times 2.1847\times10^{8}}{ 6.626\times10^{-27}\times 3}$

$\Rightarrow 3$

Hence (b) is the correct answer.

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