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Questions  >>  CBSE XII  >>  Math  >>  Model Papers
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Find the vector equation of the line through the point ( 1, 2, -4 ) and perpendicular to the two lines $\large \frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7} $ and, $ \large\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5} $

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