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An oil drop has $8.01\times10^{-19}$ C charge. Calculate the number of electrons in this drop.

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A)
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Charge on oil drop = $8.01\times10^{-19}$
$\because 1.602 \times 10^{-19}$ is charge on one electron
$\therefore 8.01\times10^{-19} $ charge on = $\large\frac{ 8.01\times10^{-19} } {1.602 \times 10^{-19} } = 5$ electrons
Hence answer is (d)
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