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Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Atomic Structure

An oil drop has $8.01\times10^{-19}$ C charge. Calculate the number of electrons in this drop.

$(a)\;2\qquad(b)\;3\qquad(c)\;4\qquad(d)\;5$

1 Answer

Charge on oil drop = $8.01\times10^{-19}$
$\because 1.602 \times 10^{-19}$ is charge on one electron
$\therefore 8.01\times10^{-19} $ charge on = $\large\frac{ 8.01\times10^{-19} } {1.602 \times 10^{-19} } = 5$ electrons
Hence answer is (d)
answered Jan 23, 2014 by sharmaaparna1
edited Mar 21, 2014 by mosymeow_1
 

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