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# Strength of $2N$ $H_2O_2$ solution is approx

$\begin{array}{1 1}(a)\;10volumes\\(b)\;11.2volumes\\(c)\;22.4volumes\\(d)\;1.12volumes\end{array}$

Therefore, $2 = \large\frac{wt}{17}$ or $wt = 2 \times 17 = 34 g$
Now, from equation we know that 68 g of $H_2O_2$ gives 22.4 L of Oxygen.
Therefore, 25.5 g of Hydrogen peroxide gives- $\large\frac{22.4 \times 34}{68} = 11.2 L$