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Show that the right circular cone of least curved surface and given volume has an altitude equal to \( \sqrt 2\) times the radius of the base.
cbse
class12
modelpaper
2012
sec-c
q25
math
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Jan 3, 2013
by
thanvigandhi_1
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Show that the right-circular cone of least curved surface and given volume has an altitude equal to \( \sqrt 2 \) times the radius of the base.
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Show that the right circular cone of least curved surface and given volume has an altitude equal to \(\sqrt 2\) time the radius of the base.
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Show that the right circular cone of least curved surface area and given volume is $\sqrt 2 $ times the radius of the base.
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Show that the semi-vertical angle of the right circular cone of given total surface area and maximum volume is \( sin^{-1} \frac{1}{3} \).
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Show that semi vertical angle of right circular cone of given surface area and maximum volume is $ \sin^{-1} \bigg( \large\frac{1}{3} \bigg). $
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Feb 2, 2013
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