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# 50ml of certain sample of $H_2O_2$ gives 1200ml of $O_2$ at STP.The volume strength of $H_2O_2$ is

$\begin{array}{1 1}(a)\;22.4v\\(b)\;20v\\(c)\;24v\\(d)\;11.2v\end{array}$

Volume strength of $H_2O_2=\large\frac{1200}{50}$
$\Rightarrow 24v$
Hence (c) is the correct answer.