Path difference $=\delta =1 \times 10^{-6}$

$\qquad= 2 \times 5 \times 10^{-7}$

$\qquad= 2 \times 5000 \times 10^{-10}$

$\qquad =2 \lambda$

Since path difference is integral multiple $\lambda$ it is a bright fringe

Since $n=2$

Second bright fringe is formed

Hence c is the correct answer.