Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

S1 : The function $f(x)=|x|$ is not one-one.\[\] S2: The negative real numbers are not the images of any real numbers. \[\] If the statement S1 holds true then,

$\begin {array} {1 1} \text{(A) S2 is true and a correct explanation of S1} \\ \text{(B) S2 is false} \\ \text{(C) S2 is true and is not a correct explanation of S1} \\ \text{(D) D.None of these} \end {array}$

Can you answer this question?

1 Answer

0 votes
Ans : (B)
Given, $f(x)=|x|$
So,$f(-x)=|-x|=f(x)$ i.e, function is many-one.
Hence S1 is true only if S2 is false.
answered Jan 23, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App