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S1 : The function $f(x)=|x|$ is not one-one.\[\] S2: The negative real numbers are not the images of any real numbers. \[\] If the statement S1 holds true then,

$\begin {array} {1 1} \text{(A) S2 is true and a correct explanation of S1} \\ \text{(B) S2 is false} \\ \text{(C) S2 is true and is not a correct explanation of S1} \\ \text{(D) D.None of these} \end {array}$

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Ans : (B)
Given, $f(x)=|x|$
So,$f(-x)=|-x|=f(x)$ i.e, function is many-one.
Hence S1 is true only if S2 is false.
answered Jan 23, 2014 by thanvigandhi_1
 

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