# Sum of the series $\;\large\frac{2}{5}+\large\frac{3}{5^2}+\large\frac{4}{5^3}+\large\frac{2}{5^4}+\large\frac{3}{5^5}+\large\frac{4}{5^6}+...$ equals:
$(a)\;\large\frac{71}{124}\qquad(b)\;\large\frac{69}{124}\qquad(c)\;\large\frac{35}{124}\qquad(d)\;\large\frac{49}{124}$