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Sum of the series $\;\large\frac{2}{5}+\large\frac{3}{5^2}+\large\frac{4}{5^3}+\large\frac{2}{5^4}+\large\frac{3}{5^5}+\large\frac{4}{5^6}+...$ equals:

$(a)\;\large\frac{71}{124}\qquad(b)\;\large\frac{69}{124}\qquad(c)\;\large\frac{35}{124}\qquad(d)\;\large\frac{49}{124}$

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