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The proposition $ (p \Rightarrow \: ^{\sim}p) \wedge (^{\sim}p \Rightarrow p)$ is a

$\begin {array} {1 1} (A)\;tautology\: and\: contradiction & \quad (B)\;neither\: tautology\: nor \: contradiction \\ (C)\;contradiction & \quad (D)\;tautology \end {array}$

1 Answer

p $ ^{\sim}p$ $ p \Rightarrow \: ^{\sim}p$ $ ^{\sim}p \Rightarrow p$ $ (p \Rightarrow \:  ^{\sim}p) \wedge (^{\sim}p \: \Rightarrow  p)$
T F F T F
F T T F F
Ans : (C)
Thus the given proposition is a contradiction.

 

answered Jan 23, 2014 by thanvigandhi_1
edited Jan 23, 2014 by thanvigandhi_1
 

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