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# When $H_2O_2$ reacts with chlorine the product obtained is

$\begin{array}{1 1}(a)\;O_2\\(b)\;H_2\\(c)\;ClO_2\\(d)\;HOCl\end{array}$

$H_2O_2+Cl_2\rightarrow 2HCl+O_2$
Hence (a) is the correct answer.