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Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Hydrogen

$PbS+H_2O_2\rightarrow H_2O$+________

$\begin{array}{1 1}(a)\;PbSO_3\\(b)\;PbSO_4\\(c)\;Pb(SO_4)_2\\(d)\;Pb_2(SO_4)_3\end{array}$

1 Answer

$PbS+H_2O_2\rightarrow H_2O+PbSO_4$
Lead(II) sulfide react with hydrogen peroxide to produce lead(II) sulfate and water.
Hence (b) is the correct answer.
answered Jan 23, 2014 by sreemathi.v
edited Oct 26, 2017 by sharmaaparna1
 
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